Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

There was a box of stamps. Grace took 
(1)/(4) of the stamps and an additional 5 stamps. Melissa took 
(2)/(5) of the remainder and an additional 3 stamps. There were 84 stamps left in the box. How many stamps were in the box at first?

There was a box of stamps. Grace took 14 \frac{1}{4} of the stamps and an additional 55 stamps. Melissa took 25 \frac{2}{5} of the remainder and an additional 33 stamps. There were 8484 stamps left in the box. How many stamps were in the box at first?

Full solution

Q. There was a box of stamps. Grace took 14 \frac{1}{4} of the stamps and an additional 55 stamps. Melissa took 25 \frac{2}{5} of the remainder and an additional 33 stamps. There were 8484 stamps left in the box. How many stamps were in the box at first?
  1. Denote Stamps as SS: Let's denote the total number of stamps at first as SS. Grace took 14\frac{1}{4} of the stamps and an additional 55 stamps. So, the stamps taken by Grace can be represented as 14S+5\frac{1}{4}S + 5.
  2. Grace's Stamps Calculation: After Grace took her share, the remainder of the stamps is S(14S+5)S - \left(\frac{1}{4}S + 5\right). This simplifies to 34S5\frac{3}{4}S - 5.
  3. Remaining Stamps After Grace: Melissa then took (25)(\frac{2}{5}) of the remainder and an additional 33 stamps. The stamps taken by Melissa can be represented as (25)((34)S5)+3(\frac{2}{5})((\frac{3}{4})S - 5) + 3.
  4. Melissa's Stamps Calculation: After Melissa took her share, there were 8484 stamps left. So, the equation representing the situation after Melissa took her share is:\newline(34)S5[(25)((34)S5)+3]=84. \left(\frac{3}{4}\right)S - 5 - \left[\left(\frac{2}{5}\right)\left(\left(\frac{3}{4}\right)S - 5\right) + 3\right] = 84.
  5. Equation After Melissa: Let's simplify the equation step by step. First, distribute the (25)(\frac{2}{5}) across the terms inside the brackets: (34)S5(25)(34)S+(25)(5)3=84(\frac{3}{4})S - 5 - (\frac{2}{5})(\frac{3}{4})S + (\frac{2}{5})(5) - 3 = 84.
  6. Distribute (25)(\frac{2}{5}): Simplify the terms: (\frac{\(3\)}{\(4\)})S - \(5 - (\frac{33}{1010})S + 22 - 33 = 8484.
  7. Combine Like Terms: Combine like terms: (\frac{\(3\)}{\(4\)})S - (\frac{\(3\)}{\(10\)})S - \(5 + 22 - 33 = 8484\.
  8. Combine S and Constants: Further simplify by combining the S terms and the constant terms: (3040)S(1240)S6=84(\frac{30}{40})S - (\frac{12}{40})S - 6 = 84.
  9. Simplify S Terms: Simplify the S terms: (1840)S6=84(\frac{18}{40})S - 6 = 84.
  10. Simplify Fraction: Simplify the fraction (1840)(\frac{18}{40}) to (920)(\frac{9}{20}):(920)S6=84.(\frac{9}{20})S - 6 = 84.
  11. Add 66 to Isolate S: Add 66 to both sides of the equation to isolate the term with S:\newline(920)S=84+6(\frac{9}{20})S = 84 + 6.
  12. Simplify Right Side: Simplify the right side of the equation: (920)S=90(\frac{9}{20})S = 90.
  13. Multiply by Reciprocal: Multiply both sides by the reciprocal of (920)(\frac{9}{20}) to solve for SS:S=90×(209).S = 90 \times \left(\frac{20}{9}\right).
  14. Simplify Multiplication: Simplify the multiplication: S=10×20S = 10 \times 20.
  15. Final Value of S: Calculate the final value of S: S=200S = 200.