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There is an exponential function that is yy positive and decreasing. Two coordinates are (0,3600)(0, 3600) and (2,225)(2,225). What is the equation

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Q. There is an exponential function that is yy positive and decreasing. Two coordinates are (0,3600)(0, 3600) and (2,225)(2,225). What is the equation
  1. Identify Form of Function: Identify the general form of the exponential function: y=abxy = a b^{x}. Here, aa is the initial value, and bb is the base of the exponential function.
  2. Find Initial Value 'a': Use the given point (0,3600)(0, 3600) to find 'a'. Substituting x=0x = 0 and y=3600y = 3600 into the equation y=abxy = ab^x gives 3600=ab03600 = ab^0. Since anything raised to the power of 00 is 11, we have 3600=a×13600 = a \times 1, so a=3600a = 3600.
  3. Find Base 'b': Use the second point (2,225)(2, 225) and the value of 'a' to find 'b'. Substituting x=2x = 2 and y=225y = 225 into the equation y=3600b2y = 3600b^2 gives 225=3600b2225 = 3600b^2. Solving for bb, we get b2=2253600=116b^2 = \frac{225}{3600} = \frac{1}{16}. Taking the square root of both sides, b=14b = \frac{1}{4} or b=14b = -\frac{1}{4}. Since the function is decreasing, we choose b=14b = \frac{1}{4}.
  4. Write Final Equation: Write the final equation using the values of aa and bb. The equation of the exponential function is y=3600(14)xy = 3600(\frac{1}{4})^x.

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