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There is a spinner with 2020 equally likely sections, numbered from 11 to 2020. You have the opportunity to spin it. If the number is even, you win $17\$17. If the number is odd, you win nothing. If you play the game, what is the expected payoff?\newline$\$____

Full solution

Q. There is a spinner with 2020 equally likely sections, numbered from 11 to 2020. You have the opportunity to spin it. If the number is even, you win $17\$17. If the number is odd, you win nothing. If you play the game, what is the expected payoff?\newline$\$____
  1. Calculate probability of even: Calculate the probability of spinning an even number. There are 1010 even numbers (22, 44, 66, 88, 1010, 1212, 1414, 1616, 1818, 2200) out of 2200 total numbers. So, 2222.
  2. Calculate probability of odd: Calculate the probability of spinning an odd number. There are 1010 odd numbers (11, 33, 55, 77, 99, 1111, 1313, 1515, 1717, 1100) out of 1111 total numbers. So, 1122.
  3. Calculate expected payoff for even: Calculate the expected payoff for spinning an even number. Expected payoff for even = P(even)×Amount won for evenP(\text{even}) \times \text{Amount won for even}. Expected payoff for even = 12×$(17)\frac{1}{2} \times \$(17).
  4. Calculate expected payoff for odd: Calculate the expected payoff for spinning an odd number. Expected payoff for odd = P(odd)×Amount won for oddP(\text{odd}) \times \text{Amount won for odd}. Expected payoff for odd = 12×$(0)\frac{1}{2} \times \$(0).
  5. Add expected payoffs: Add the expected payoffs for even and odd numbers to get the total expected payoff. Total expected payoff = Expected payoff for even + Expected payoff for odd. Total expected payoff = (12($)17)+(12($)0)(\frac{1}{2} * (\$)17) + (\frac{1}{2} * (\$)0).
  6. Perform calculations: Perform the calculations to find the total expected payoff. Total expected payoff = 0.5170.5 * 17 + 0.500.5 * 0. Total expected payoff = $8.5\$8.5 + $0\$0. Total expected payoff = $8.5\$8.5.

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