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There is a line that includes the point (7,6)(-7,-6) and has a slope of 15\frac{1}{5}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newlineyy - ______= = ______(x(x - ______))

Full solution

Q. There is a line that includes the point (7,6)(-7,-6) and has a slope of 15\frac{1}{5}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newlineyy - ______= = ______(x(x - ______))
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlinePoint-slope form: yy1=m(xx1)y - y_1 = m(x - x_1)
  2. Substitute Values: We have:\newlinePoint: (7,6)(-7, -6)\newlineSlope: 15\frac{1}{5}\newlineWhat is the point-slope form of the line?\newlineSubstitute 15\frac{1}{5} for mm, 7-7 for x1x_1, and 6-6 for y1y_1 in point-slope form.\newliney(6)=(15)(x(7))y - (-6) = \left(\frac{1}{5}\right)(x - (-7))
  3. Simplify Equation: Simplify the equation. y+6=15(x+7)y + 6 = \frac{1}{5}(x + 7)

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