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There are 33 consecutive integers with a sum of 1818. Which integers are they?\newline_\_, _\_, _\_

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Q. There are 33 consecutive integers with a sum of 1818. Which integers are they?\newline_\_, _\_, _\_
  1. Identify First Integer: Let xx be the first integer. \newlineWhich represents the three consecutive integers?\newlineConsecutive integers increase by 11 each time. \newlineConsecutive integers: xx, x+1x+1, x+2x+2
  2. Sum of Consecutive Integers: Which equation represents the sum of 33 consecutive integers is 1818?\newlineAdd three consecutive integers and equate the sum to 1818.\newlineEquation: x+(x+1)+(x+2)=18x + (x+1) + (x+2) = 18
  3. Simplify Equation: Simplify the left side of x+(x+1)+(x+2)=18x + (x+1) + (x+2) = 18.\newlinex+(x+1)+(x+2)=18x + (x+1) + (x+2) = 18\newline(x+x+x)+(1+2)=18(x + x + x) + (1+2) = 18\newline3x+3=183x + 3 = 18
  4. Isolate Variable Term: Isolate the variable term in 3x+3=183x + 3 = 18. \newline3x+3=183x + 3 = 18 \newline3x+3−3=18−33x + 3 - 3 = 18 - 3 \newline3x=153x = 15
  5. Solve for x: 3x=153x = 15 \newlineSolve for x.\newline3x=153x = 15 \newline(3x)/3=15/3(3x)/3 = 15/3 \newlinex=5x = 5
  6. Final Consecutive Integers: We have: \newlinex=5x = 5 \newlineWhat are the 33 consecutive integers that add up to 1818?\newlineThree consecutive integers: \newlinex,x+1,x+2x, x+1, x+2 \newline5,5+1,5+25, 5+1, 5+2 \newline5,6,75, 6, 7

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