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The volume of a right cone is 
1680 pi units 
^(3). If its radius measures 12 units, find its height.
Answer: units

The volume of a right cone is 1680π 1680 \pi units 3 ^{3} . If its radius measures 1212 units, find its height.\newlineAnswer: units

Full solution

Q. The volume of a right cone is 1680π 1680 \pi units 3 ^{3} . If its radius measures 1212 units, find its height.\newlineAnswer: units
  1. Write Volume Formula: The formula for the volume of a right cone is V=13πr2hV = \frac{1}{3}\pi r^2 h, where VV is the volume, rr is the radius, and hh is the height of the cone. We are given the volume V=1680πV = 1680\pi units3^3 and the radius r=12r = 12 units. We need to solve for the height hh.
  2. Substitute Known Values: First, let's plug the known values into the volume formula: 1680π=(13)π(12)2h1680\pi = \left(\frac{1}{3}\right)\pi(12)^2h.
  3. Simplify Equation: Next, we simplify the right side of the equation by squaring the radius: 1680π=(13)π(144)h1680\pi = (\frac{1}{3})\pi(144)h.
  4. Cancel π\pi: Now, we can cancel π\pi from both sides of the equation, which gives us 1680=(1/3)(144)h1680 = (1/3)(144)h.
  5. Isolate Term with hh: We multiply both sides of the equation by 33 to isolate the term with hh: 5040=144h5040 = 144h.
  6. Solve for h: Finally, we divide both sides by 144144 to solve for hh: h=5040144h = \frac{5040}{144}.
  7. Final Height: After performing the division, we find that h=35h = 35 units.

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