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The value of 
y varies directly with 
x, and when 
x=(1)/(4),y=25. What is the value of 
y when 
x is 
2(1)/(3) ?
A. 
233(1)/(3)
B. 
9(1)/(3)
C. 
14(1)/(2)
D. 
213(1)/(4)

33. The value of y y varies directly with x x , and when x=14,y=25 x=\frac{1}{4}, y=25 . What is the value of y y when x x is 213 2 \frac{1}{3} ?\newlineA. 23313 233 \frac{1}{3} \newlineB. 913 9 \frac{1}{3} \newlineC. 1412 14 \frac{1}{2} \newlineD. 21314 213 \frac{1}{4}

Full solution

Q. 33. The value of y y varies directly with x x , and when x=14,y=25 x=\frac{1}{4}, y=25 . What is the value of y y when x x is 213 2 \frac{1}{3} ?\newlineA. 23313 233 \frac{1}{3} \newlineB. 913 9 \frac{1}{3} \newlineC. 1412 14 \frac{1}{2} \newlineD. 21314 213 \frac{1}{4}
  1. Identify Relationship: Identify the direct variation relationship between yy and xx. Given y=25y = 25 when x=14x = \frac{1}{4}, find the constant of variation kk. Use the formula y=kxy = kx.\newlineCalculation: 25=k×(14)25 = k \times \left(\frac{1}{4}\right)\newlineSolving for kk gives k=25×4=100k = 25 \times 4 = 100.
  2. Find Constant of Variation: Use the constant of variation kk to find yy when x=2(1)3x = \frac{2(1)}{3}. Convert the mixed number to an improper fraction.\newlineCalculation: 2(13)=732\left(\frac{1}{3}\right) = \frac{7}{3}.\newlineNow, y=100×(73)=7003=233(13)y = 100 \times \left(\frac{7}{3}\right) = \frac{700}{3} = 233\left(\frac{1}{3}\right).

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