The U.S. Senate has 100 members. After a certain election, there were 12 more Democrats than Republicans, with no other parties represented. How many members of each party were there in the Senate?□ Democrats□ Republicans
Q. The U.S. Senate has 100 members. After a certain election, there were 12 more Democrats than Republicans, with no other parties represented. How many members of each party were there in the Senate?□ Democrats□ Republicans
Define Variables: Let's call the number of Democrats D and the number of Republicans R. We know that D=R+12 because there are 12 more Democrats than Republicans.
Total Senate Members: We also know that the total number of Senate members is 100. So, D+R=100.
Substitute and Solve: Now we have two equations: D=R+12 and D+R=100. We can substitute the first equation into the second one to find R.
Combine Like Terms: Substituting D from the first equation into the second, we get (R+12)+R=100.
Isolate Term with R: Combining like terms, we get 2R+12=100.
Solve for R: Subtract 12 from both sides to isolate the term with R, we get 2R=100−12, which is 2R=88.
Find D: Divide both sides by 2 to solve for R, we get R=288, which is R=44.
Calculate D: Now that we have R, we can find D by plugging R back into the first equation: D=R+12. So, D=44+12.
Check Total: Calculating D gives us D=56. So, there are 56 Democrats.
Check Total: Calculating D gives us D=56. So, there are 56 Democrats. We've found that there are 44 Republicans and 56 Democrats. Let's check if the total adds up to 100: 44+56=100.
More problems from Find a value using two-variable equations: word problems