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The tires of a go-kart are
1m in circumference. The tires revolve 15 times per second.
What is the distance the go-kart travels in 40 seconds?
m

The tires of a go-kart are $1 \mathrm{~m}$ in circumference. The tires revolve $15$ times per second. $\newline$ What is the distance the go-kart travels in $40$ seconds? $\newline$ $\square$ m

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Pythagorean Theorem and its converse

Full solution

Q. The tires of a go-kart are

1 \mathrm{~m}

in circumference. The tires revolve

15

times per second.

\newline

What is the distance the go-kart travels in

40

seconds?

\newline

\square

m

Calculate Distance Traveled: Calculate the distance traveled in one second by multiplying the number of revolutions by the circumference of the tires. $\newline$ Distance in one second = Number of revolutions per second $\times$ Circumference of tires $\newline$ Distance in one second = $15 \, \text{rev/s} \times 1 \, \text{m/rev}$
Find Total Distance: Multiply the distance traveled in one second by the number of seconds to find the total distance. $\newline$ Total distance $= \text{Distance in one second} \times \text{Time in seconds}$ $\newline$ Total distance $= 15 \, \text{m/s} \times 40 \, \text{s}$
Perform Multiplication: Perform the multiplication to find the total distance. $\newline$ Total distance = $600\,\text{m}$

More problems from Pythagorean Theorem and its converse

Question

Marco's class is painting a mural on the side of their school. The mural covers a

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What is the length of the mural?

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A cup of hot coffee has been left to cool in a room with an ambient temperature of

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The relationship between the elapsed time,

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, is modeled by the following function.

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T(m)=21+74 \cdot 10^{-0.03 m}

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What will the temperature of the coffee be after

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{ }^{\circ} C

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Takumi plants a tree in his backyard and studies how the number of branches grows over time.

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N=5 \cdot 10^{0.3 t}

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g(x)=2^{x}

\newline

Can we use the mean value theorem to say the equation

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\newline

1

\newline

(A) No, since the function is not differentiable on that interval.

\newline

(B) No, since the average rate of change of

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1 \overline{6}

\newline

(C) Yes, both conditions for using the mean value theorem have been met.

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