The table gives selected values of the differentiable function f. Below is Leo's attempt to write a formal justification for the fact that there exists a value c where a<c<b such that f′(c)=b−af(b)−f(a). Is Leo's justification complete? If not, why? Leo's justification: f is differentiable on [a,b]. So, according to the mean value theorem, there exists a value c somewhere between a and b such that f′(c)=b−af(b)−f(a).
Q. The table gives selected values of the differentiable function f. Below is Leo's attempt to write a formal justification for the fact that there exists a value c where a<c<b such that f′(c)=b−af(b)−f(a). Is Leo's justification complete? If not, why? Leo's justification: f is differentiable on [a,b]. So, according to the mean value theorem, there exists a value c somewhere between a and b such that f′(c)=b−af(b)−f(a).
Check Criteria: To apply the Mean Value Theorem, we need to ensure that the function f is continuous on the closed interval [a,b] and differentiable on the open interval (a,b). We also need the values of f at a and b to calculate the average rate of change.
Calculate Average Rate: Assuming the function meets the criteria for the Mean Value Theorem, we calculate the average rate of change of f on [a,b] by using the formula b−af(b)−f(a).
State Mean Value Theorem: Next, we would state the Mean Value Theorem, which says that if f is continuous on [a,b] and differentiable on (a,b), then there exists at least one c in (a,b) such that f′(c) is equal to the average rate of change of f on [a,b].
Verify Leo's Justification: We would then check Leo's justification to see if he has correctly identified the function values at a and b, calculated the average rate of change, and correctly stated the conditions under which the Mean Value Theorem applies.
Evaluate Completeness: If Leo's justification includes all the necessary components and calculations, then it is complete. If any information is missing or incorrect, then the justification is not complete.
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