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The system has no solution.\newlineThe system has a unique solution:\newline(x,y)=(,)(x,y)=(\square,\square)\newline\begin{cases}x+2y=8\-x-2y=8\end{cases}\newlineThe system has infinitely many solutions.\newlineThey must satisfy the following equation:\newliney=

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Q. The system has no solution.\newlineThe system has a unique solution:\newline(x,y)=(,)(x,y)=(\square,\square)\newline\begin{cases}x+2y=8\-x-2y=8\end{cases}\newlineThe system has infinitely many solutions.\newlineThey must satisfy the following equation:\newliney=
  1. Analyze Equations: Analyze the system of equations to determine if there is a solution.\newlineThe system of equations is:\newline11. x+2y=8x + 2y = 8\newline22. x2y=8-x - 2y = 8\newlineWe can add the two equations together to see if they are consistent or inconsistent.\newlineAdding equation 11 and equation 22 gives us:\newline(x+2y)+(x2y)=8+8(x + 2y) + (-x - 2y) = 8 + 8\newlineThis simplifies to:\newline0=160 = 16\newlineSince 0160 \neq 16, this indicates that the system is inconsistent.
  2. Determine Consistency: Conclude the type of solution the system has based on the inconsistency found in Step 11.\newlineBecause we have found an inconsistency, the system has no solution. There is no need to proceed further with solving for xx or yy since the equations contradict each other.

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