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The profit for a product is given by \newlineP(x)=11x2+770x6600P(x)=-11x^{2}+770x-6600, where \newlinexx is the number of units produced and sold. How many units give break even (that is, give zero profit) for this product?\newlineThe number of units that give the break even for this product are \newline000\boxed{\phantom{000}}. \newline(Use a comma to separate answers as needed.)

Full solution

Q. The profit for a product is given by \newlineP(x)=11x2+770x6600P(x)=-11x^{2}+770x-6600, where \newlinexx is the number of units produced and sold. How many units give break even (that is, give zero profit) for this product?\newlineThe number of units that give the break even for this product are \newline000\boxed{\phantom{000}}. \newline(Use a comma to separate answers as needed.)
  1. Set Profit Function Equal: Set the profit function equal to zero to find the break-even points. \newlineP(x)=11x2+770x6600P(x) = -11x^2 + 770x - 6600\newlineTo find the break-even points, we need to solve for xx when P(x)=0P(x) = 0.\newline0=11x2+770x66000 = -11x^2 + 770x - 6600
  2. Factor or Use Formula: Factor the quadratic equation or use the quadratic formula to find the values of xx. The quadratic formula is x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where aa, bb, and cc are the coefficients from the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0. In our case, a=11a = -11, b=770b = 770, and c=6600c = -6600.
  3. Calculate Discriminant: Calculate the discriminant b24acb^2 - 4ac to ensure that the roots are real numbers.\newlineDiscriminant = b24ac=(770)24(11)(6600)b^2 - 4ac = (770)^2 - 4(-11)(-6600)\newlineDiscriminant = 592900290400592900 - 290400\newlineDiscriminant = 302500302500\newlineSince the discriminant is positive, we have two real roots.
  4. Apply Quadratic Formula: Apply the quadratic formula to find the roots.\newlinex=770±3025002×11x = \frac{-770 \pm \sqrt{302500}}{2 \times -11}\newlinex=770±55022x = \frac{-770 \pm 550}{-22}
  5. Solve for Values: Solve for the two values of xx.
    x1=770+55022x_1 = \frac{{-770 + 550}}{{-22}}
    x1=22022x_1 = \frac{{-220}}{{-22}}
    x1=10x_1 = 10

    x2=77055022x2 = \frac{{-770 - 550}}{{-22}}
    x2=132022x2 = \frac{{-1320}}{{-22}}
    x2=60x2 = 60
  6. Verify Valid Solutions: Verify that the roots make sense in the context of the problem.\newlineSince we are looking for the number of units produced and sold, negative values do not make sense. Both 1010 and 6060 are positive, so they are valid solutions for the number of units that give break-even.

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