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The price value, VV, of a car that is tt years old is given by V=f(t)=170003100tV=f(t)=17000-3100t. Find the domain and range of f(t)f(t).

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Q. The price value, VV, of a car that is tt years old is given by V=f(t)=170003100tV=f(t)=17000-3100t. Find the domain and range of f(t)f(t).
  1. Identify Function Components: Identify the function and its components.\newlineFunction: V=f(t)=170003100tV = f(t) = 17000 - 3100t\newlineThis equation shows how the value VV of a car decreases over time tt.
  2. Determine Domain of f(t)f(t): Determine the domain of f(t)f(t). The domain of f(t)f(t) is all possible values of tt for which the function is defined. Since tt represents the age of the car in years, tt must be a non-negative number (t0t \geq 0).
  3. Calculate Zero Value Time: Calculate when the car's value reaches zero to find the upper limit of the domain.\newlineSet V=0V = 0 and solve for tt:\newline0=170003100t0 = 17000 - 3100t\newline3100t=170003100t = 17000\newlinet=170003100t = \frac{17000}{3100}\newlinet=5.48t = 5.48\newlineSince a car can't be a fraction of a year old in this context, round tt down to the nearest whole number, t=5t = 5.
  4. State Domain Limit: State the domain based on the calculation.\newlineThe domain of f(t)f(t) is 0t50 \leq t \leq 5, as the car's value cannot be negative and the car is valued for up to 55 years.
  5. Determine Range of f(t): Determine the range of f(t)f(t). The range of f(t)f(t) is the set of all possible values of VV. From t=0t = 0 to t=5t = 5, the value of VV decreases from 1700017000 to 00.
  6. State Range Values: State the range based on the function's behavior.\newlineThe range of f(t)f(t) is from 00 to 1700017000, as these are the maximum and minimum values VV can take.

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