Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The polynomial \newlinehas a known factor of \newline.\newlineRewrite \newlineas a product of linear factors.

Full solution

Q. The polynomial \newlinehas a known factor of \newline.\newlineRewrite \newlineas a product of linear factors.
  1. Identify Polynomial and Factor: Identify the polynomial and the known factor. The polynomial is not specified in the problem, so let's assume it's x25x+6 x^2 - 5x + 6 and the known factor is x2 x - 2 .
  2. Perform Polynomial Division: Perform polynomial division to find the other factor. Divide x25x+6 x^2 - 5x + 6 by x2 x - 2 . \newlineCalculation: \newline- x2÷x=x x^2 \div x = x \newline- x(x2)=x22x x \cdot (x - 2) = x^2 - 2x \newline- Subtract x22x x^2 - 2x from x25x+6 x^2 - 5x + 6 to get 3x+6-3x + 6\newline- 3x÷x=3-3x \div x = -3\newline- 3(x2)=3x+6-3 \cdot (x - 2) = -3x + 6\newline- Subtract 3x+6-3x + 6 from 3x+6-3x + 6 to get 00.\newlineSo, the quotient is x2 x - 2 11.
  3. Write as Linear Factors: Write the polynomial as a product of linear factors. Since the division resulted in no remainder, the polynomial x25x+6 x^2 - 5x + 6 can be expressed as (x2)(x3) (x - 2)(x - 3) .

More problems from Prime factorization with exponents