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$The owner of a sushi restaurant looked over some recent orders. He noted how many yellowtail and salmon rolls had been ordered. Not spicy Spicy Yellowtail 2 2 Salmon 3 4 What is the probability that a randomly selected sushi roll contains yellowtail and is not spicy? Simplify any fractions. ◻$

The owner of a sushi restaurant looked over some recent orders. He noted how many yellowtail and salmon rolls had been ordered. $\newline$ \begin{tabular}{|l|c|c|} $\newline$ \cline { $2$ - $3$ } & Not spicy & Spicy \\ $\newline$ \hline Yellowtail & $2$ & $2$ \\ $\newline$ \hline Salmon & $3$ & $4$ \\ $\newline$ \hline $\newline$ \end{tabular} $\newline$ What is the probability that a randomly selected sushi roll contains yellowtail and is not spicy? $\newline$ Simplify any fractions. $\newline$ $\square$

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Probability of independent and dependent events

Full solution

Q. The owner of a sushi restaurant looked over some recent orders. He noted how many yellowtail and salmon rolls had been ordered.

\newline

\begin{tabular}{|l|c|c|}

\newline

\cline {

2

-

3

} & Not spicy & Spicy \\

\newline

\hline Yellowtail &

2

&

2

\\

\newline

\hline Salmon &

3

&

4

\\

\newline

\hline

\newline

\end{tabular}

\newline

What is the probability that a randomly selected sushi roll contains yellowtail and is not spicy?

\newline

Simplify any fractions.

\newline

\square

Calculate Yellowtail Rolls: Total number of yellowtail rolls (spicy and not spicy) = $2$ (not spicy) + $2$ (spicy) = $4$ .
Calculate Total Sushi Rolls: Total number of sushi rolls = $2$ (not spicy yellowtail) + $2$ (spicy yellowtail) + $3$ (not spicy salmon) + $4$ (spicy salmon) = $11$ .
Calculate Probability: Probability of selecting a yellowtail roll that is not spicy = Number of not spicy yellowtail rolls / Total number of sushi rolls = $\frac{2}{11}.$

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\newline

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