Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The number 22 is increased to 39 . What is the percentage by which the number was increased, to the nearest tenth of a percent? Answer:

The number 2222 is increased to 3939 . What is the percentage by which the number was increased, to the nearest tenth of a percent?\newlineAnswer:

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Geometryright chevron icon
Percent errorright chevron icon

Full solution

Q. The number 2222 is increased to 3939 . What is the percentage by which the number was increased, to the nearest tenth of a percent?\newlineAnswer:
  1. Determine Increase Amount: Determine the amount of increase from the original number.\newlineTo find the increase, subtract the original number from the new number.\newlineIncrease =New number−Original number= \text{New number} - \text{Original number}\newlineIncrease =39−22= 39 - 22\newlineIncrease =17= 17
  2. Calculate Percentage Increase: Calculate the percentage increase based on the original number.\newlineTo find the percentage increase, divide the increase by the original number and then multiply by 100100 to convert it to a percentage.\newlinePercentage increase = (Increase÷Original number)×100(\text{Increase} \div \text{Original number}) \times 100\newlinePercentage increase = (17÷22)×100(17 \div 22) \times 100
  3. Perform Division and Multiplication: Perform the division and multiplication to find the percentage increase.\newlinePercentage increase = (17÷22)×100(17 \div 22) \times 100\newlinePercentage increase ≈0.7727×100\approx 0.7727 \times 100\newlinePercentage increase ≈77.27\approx 77.27
  4. Round Percentage Increase: Round the percentage increase to the nearest tenth of a percent.\newlineRounded percentage increase ≈77.3%\approx 77.3\%

More problems from Percent error

Question
An element with mass 230230 grams decays by 27.7% 27.7 \% per minute. How much of the element is remaining after 88 minutes, to the nearest 11oth of a gram?\newlineAnswer:
Get tutor helpright-arrow

Posted 2 months ago

Question
An element with mass 910910 grams decays by 16.6% 16.6 \% per minute. How much of the element is remaining after 2020 minutes, to the nearest 11oth of a gram?\newlineAnswer:
Get tutor helpright-arrow

Posted 2 months ago

Question
An element with mass 990990 grams decays by 18.8% 18.8 \% per minute. How much of the element is remaining after 1313 minutes, to the nearest 11oth of a gram?\newlineAnswer:
Get tutor helpright-arrow

Posted 2 months ago

Question
An element with mass 570570 grams decays by 15.2% 15.2 \% per minute. How much of the element is remaining after 1616 minutes, to the nearest 11oth of a gram?\newlineAnswer:
Get tutor helpright-arrow

Posted 2 months ago

Question
An element with mass 490490 grams decays by 18.8% 18.8 \% per minute. How much of the element is remaining after 88 minutes, to the nearest 11oth of a gram?\newlineAnswer:
Get tutor helpright-arrow

Posted 2 months ago

Question
The number 3535 is increased to 3737 . What is the percentage by which the number was increased, to the nearest tenth of a percent?\newlineAnswer:
Get tutor helpright-arrow

Posted 2 months ago

Question
The number 3232 is increased to 3535 . What is the percentage by which the number was increased, to the nearest tenth of a percent?\newlineAnswer:
Get tutor helpright-arrow

Posted 2 months ago

Question
The number 3333 is decreased to 3232 . What is the percentage by which the number was decreased, to the nearest tenth of a percent?\newlineAnswer:
Get tutor helpright-arrow

Posted 2 months ago

Question
The number 3535 is decreased to 3232 . What is the percentage by which the number was decreased, to the nearest tenth of a percent?\newlineAnswer:
Get tutor helpright-arrow

Posted 2 months ago

Question
Khan Academy\newlineLímites por susti\newlineGoogle\newlinePuede que necesites:\newlinelim⁡x→2(x3−5x2+1)= \lim _{x \rightarrow 2}\left(x^{3}-5 x^{2}+1\right)= \newlineEsconder calculadora\newlineCalculadora
Get tutor helpright-arrow

Posted 23 hours ago

View all (33)