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The inclination (tilt) of an amusement park ride is accelerating at a rate of
2160(" degrees ")/(min2).
What is the ride's acceleration rate in
(" degrees ")/(s^(2)) ?

(" degrees ")/(s^(2))

The inclination (tilt) of an amusement park ride is accelerating at a rate of $2160 \frac{\text { degrees }}{\min ^{2}}$ . $\newline$ What is the ride's acceleration rate in $\frac{\text { degrees }}{\mathrm{s}^{2}}$ ? $\newline$ $\square$ $\frac{\text { degrees }}{\mathrm{s}^{2}}$

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Convert rates and measurements: customary units

Full solution

Q. The inclination (tilt) of an amusement park ride is accelerating at a rate of

2160 \frac{\text { degrees }}{\min ^{2}}

.

\newline

What is the ride's acceleration rate in

\frac{\text { degrees }}{\mathrm{s}^{2}}

?

\newline

\square

\frac{\text { degrees }}{\mathrm{s}^{2}}

Convert time units: To convert the acceleration rate from degrees per minute squared to degrees per second squared, we need to know how many seconds are in one minute.
Square seconds in a minute: There are $60$ seconds in one minute. To convert from minutes squared to seconds squared, we square the number of seconds in one minute. $\newline$ $(60 \text{ seconds})^2 = 3600 \text{ seconds}^2$
Divide by seconds squared: Now we divide the given acceleration rate by the number of seconds squared in one minute squared to find the acceleration rate in degrees per second squared. $\newline$ Acceleration rate in degrees per second squared = $\frac{2160 \text{ degrees per minute}^2}{3600 \text{ seconds}^2}$
Perform division: Perform the division to find the acceleration rate in degrees per second squared. $\newline$ Acceleration rate in degrees per second squared = $\frac{2160}{3600} \text{ degrees per second}^2$
Simplify fraction: Simplify the fraction by dividing both the numerator and the denominator by their greatest common factor, which is $3600$ . $\newline$ Acceleration rate in degrees per second squared = $\frac{2160}{3600}$ = $\frac{3}{5} \text{ degrees per second}^2$

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