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The homework for English class was to write a poem. The teacher wants to ask 44 students, 22 boys and 22 girls, to read their poems for the class. If there are 1010 boys and 1515 girls, how many different combinations of 22 boys and 22 girls can the teacher select?\newline[(210)(215)(425)]\left[\frac{\binom{2}{10}\cdot\binom{2}{15}}{\binom{4}{25}}\right], 2!2!10!8!2×18!18!25!24!212012!4!\frac{2!\cdot 2!}{10!\cdot 8!}\cdot\frac{2\times}{18!18!}\cdot\frac{25!\cdot 24!\cdot 21\cdot 20}{12!\cdot 4!}

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Q. The homework for English class was to write a poem. The teacher wants to ask 44 students, 22 boys and 22 girls, to read their poems for the class. If there are 1010 boys and 1515 girls, how many different combinations of 22 boys and 22 girls can the teacher select?\newline[(210)(215)(425)]\left[\frac{\binom{2}{10}\cdot\binom{2}{15}}{\binom{4}{25}}\right], 2!2!10!8!2×18!18!25!24!212012!4!\frac{2!\cdot 2!}{10!\cdot 8!}\cdot\frac{2\times}{18!18!}\cdot\frac{25!\cdot 24!\cdot 21\cdot 20}{12!\cdot 4!}
  1. Calculate Boys Combination: Calculate the number of ways to choose 22 boys out of 1010. We use the combination formula, which is C(n,k)=n!k!(nk)!C(n, k) = \frac{n!}{k!(n-k)!}, where nn is the total number of items, kk is the number of items to choose, and "!" denotes factorial. For 22 boys out of 1010, we have C(10,2)=10!2!(102)!=10!2!8!=10×92×1=45C(10, 2) = \frac{10!}{2!(10-2)!} = \frac{10!}{2!8!} = \frac{10\times9}{2\times1} = 45.
  2. Calculate Girls Combination: Calculate the number of ways to choose 22 girls out of 1515. Using the combination formula again, we have C(15,2)=15!(2!(152)!)=15!(2!13!)=(15×14)(2×1)=105C(15, 2) = \frac{15!}{(2!(15-2)!)} = \frac{15!}{(2!13!)} = \frac{(15\times14)}{(2\times1)} = 105.
  3. Calculate Total Combinations: Calculate the total number of combinations of 22 boys and 22 girls.\newlineSince the selections of boys and girls are independent events, we multiply the number of ways to choose the boys by the number of ways to choose the girls.\newlineTotal combinations = C(10,2)×C(15,2)=45×105C(10, 2) \times C(15, 2) = 45 \times 105.
  4. Perform Multiplication: Perform the multiplication to find the total number of combinations.\newlineTotal combinations = 45×105=472545 \times 105 = 4725.

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