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The graph below represents the number of minutes used versus the cost. Select the equation that matches the graph. (8.5I)
A. 
y=2.5 x+2
B. 
y=x+2
C. 
y=2.5 x
D. 
y=x^(2)

77. The graph below represents the number of minutes used versus the cost. Select the equation that matches the graph. (88.55I)\newlineA. y=2.5x+2 y=2.5 x+2 \newlineB. y=x+2 y=x+2 \newlineC. y=2.5x y=2.5 x \newlineD. y=x2 y=x^{2}

Full solution

Q. 77. The graph below represents the number of minutes used versus the cost. Select the equation that matches the graph. (88.55I)\newlineA. y=2.5x+2 y=2.5 x+2 \newlineB. y=x+2 y=x+2 \newlineC. y=2.5x y=2.5 x \newlineD. y=x2 y=x^{2}
  1. Identify y-intercept: Look at the graph's y-intercept, that's where it crosses the y-axis. The y-intercept is at (0,2)(0, 2). So, the equation must have +2+2 at the end, cuz that's where it starts. That rules out C.
  2. Calculate slope: Now, check the slope. The slope is the rise over run, right? So, if for every 11 minute (the run), the cost (the rise) goes up by $2.5\$2.5, then the slope is 2.52.5. That means the equation's gotta start with y=2.5xy=2.5x. So, AA is looking good, and BB and DD are out.
  3. Verify with point: Just to be sure, plug in a point from the graph into the equations left. Let's say we use the point (4,12)(4, 12) from the graph. If we put 44 in for xx in equation A, we get y=2.5(4)+2y=2.5(4)+2, which is y=10+2y=10+2, and that's y=12y=12. That matches the graph!
  4. Final equation: So, the equation that matches the graph is y=2.5x+2y=2.5x+2, which is option AA.

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