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The function 
f is given by 
f(x)=log_(2)x. What input value in the domain of 
f yields an output value of 4 ?
(A) 32

f(x)=log_(2)x
(B) 16
(C) 2

log_(2)8=3
(D) 
(1)/(2)

log_(2)x=4quad2^(3)=8

The function f f is given by f(x)=log2x f(x)=\log _{2} x . What input value in the domain of f f yields an output value of 44 ?\newline(A) 3232\newlinef(x)=log2x f(x)=\log _{2} x \newline(B) 1616\newline(C) 22\newlinelog28=3 \log _{2} 8=3 \newline(D) 12 \frac{1}{2} \newlinelog2x=423=8 \log _{2} x=4 \quad 2^{3}=8

Full solution

Q. The function f f is given by f(x)=log2x f(x)=\log _{2} x . What input value in the domain of f f yields an output value of 44 ?\newline(A) 3232\newlinef(x)=log2x f(x)=\log _{2} x \newline(B) 1616\newline(C) 22\newlinelog28=3 \log _{2} 8=3 \newline(D) 12 \frac{1}{2} \newlinelog2x=423=8 \log _{2} x=4 \quad 2^{3}=8
  1. Identify equation: Identify the equation to solve: f(x)=log2(x)=4f(x) = \log_2(x) = 4. We need to find xx such that the logarithm base 22 of xx equals 44.
  2. Convert to exponential form: Convert the logarithmic equation to its exponential form to solve for xx: 24=x2^4 = x.
  3. Calculate value: Calculate the value of 242^4: 24=162^4 = 16.

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