Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The force that friction exerts on a car is proportional to its mass. Suppose friction exerts 6272N6272\,\text{N} of force on a 1600kg1600\,\text{kg} car on a wet road. How many newtons of force would friction exert on a 2400kg2400\,\text{kg} car under the same conditions?

Full solution

Q. The force that friction exerts on a car is proportional to its mass. Suppose friction exerts 6272N6272\,\text{N} of force on a 1600kg1600\,\text{kg} car on a wet road. How many newtons of force would friction exert on a 2400kg2400\,\text{kg} car under the same conditions?
  1. Establish Relationship: First, we need to establish the relationship between the force of friction and the mass of the car. We are given that the force of friction is proportional to the mass of the car. This means that if we know the force exerted on a car of a certain mass, we can use a ratio to find the force exerted on a car of a different mass.
  2. Set Up Proportion: We are given that a 1600kg1600\,\text{kg} car experiences a force of 6272N6272\,\text{N}. We can set up a proportion to find the force on a 2400kg2400\,\text{kg} car. Let FF be the force on the 2400kg2400\,\text{kg} car. The proportion is:\newline(Force on 1600kg car)/(Mass of 1600kg car)=(Force on 2400kg car)/(Mass of 2400kg car)(\text{Force on } 1600\,\text{kg car}) / (\text{Mass of } 1600\,\text{kg car}) = (\text{Force on } 2400\,\text{kg car}) / (\text{Mass of } 2400\,\text{kg car})\newline6272N/1600kg=F/2400kg6272\,\text{N} / 1600\,\text{kg} = F / 2400\,\text{kg}
  3. Cross-Multiply and Solve: To find FF, we cross-multiply and solve for FF: 6272N×2400kg=F×1600kg6272 \, \text{N} \times 2400 \, \text{kg} = F \times 1600 \, \text{kg}
  4. Perform Multiplication: Now we perform the multiplication on the left side of the equation: 15,052,800Nkg=F1600kg15,052,800 \, \text{N} \cdot \text{kg} = F \cdot 1600 \, \text{kg}
  5. Divide and Solve: Next, we divide both sides of the equation by 1600kg1600 \, \text{kg} to solve for FF: \newline15,052,800Nkg1600kg=F\frac{15,052,800 \, \text{N} \cdot \text{kg}}{1600 \, \text{kg}} = F
  6. Divide and Solve: Next, we divide both sides of the equation by 1600kg1600 \, \text{kg} to solve for FF: \newline15,052,800Nkg1600kg=F\frac{15,052,800 \, \text{N} \cdot \text{kg}}{1600 \, \text{kg}} = F Performing the division gives us: \newlineF=15,052,800Nkg1600kgF = \frac{15,052,800 \, \text{N} \cdot \text{kg}}{1600 \, \text{kg}} \newlineF=9408NF = 9408 \, \text{N}

More problems from Identify quotients of rational numbers: word problems

QuestionGet tutor helpright-arrow

Posted 3 months ago