The force that friction exerts on a car is proportional to its mass. Suppose friction exerts 6272N of force on a 1600kg car on a wet road. How many newtons of force would friction exert on a 2400kg car under the same conditions?
Q. The force that friction exerts on a car is proportional to its mass. Suppose friction exerts 6272N of force on a 1600kg car on a wet road. How many newtons of force would friction exert on a 2400kg car under the same conditions?
Establish Relationship: First, we need to establish the relationship between the force of friction and the mass of the car. We are given that the force of friction is proportional to the mass of the car. This means that if we know the force exerted on a car of a certain mass, we can use a ratio to find the force exerted on a car of a different mass.
Set Up Proportion: We are given that a 1600kg car experiences a force of 6272N. We can set up a proportion to find the force on a 2400kg car. Let F be the force on the 2400kg car. The proportion is:(Force on 1600kg car)/(Mass of 1600kg car)=(Force on 2400kg car)/(Mass of 2400kg car)6272N/1600kg=F/2400kg
Cross-Multiply and Solve: To find F, we cross-multiply and solve for F: 6272N×2400kg=F×1600kg
Perform Multiplication: Now we perform the multiplication on the left side of the equation: 15,052,800N⋅kg=F⋅1600kg
Divide and Solve: Next, we divide both sides of the equation by 1600kg to solve for F: 1600kg15,052,800N⋅kg=F
Divide and Solve: Next, we divide both sides of the equation by 1600kg to solve for F: 1600kg15,052,800N⋅kg=F Performing the division gives us: F=1600kg15,052,800N⋅kgF=9408N
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