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The equation of line cc is y=−19x−10y = -\frac{1}{9}x - 10. Line dd includes the point (−9,−7)(-9,-7) and is parallel to line cc. What is the equation of line dd?\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.

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Q. The equation of line cc is y=−19x−10y = -\frac{1}{9}x - 10. Line dd includes the point (−9,−7)(-9,-7) and is parallel to line cc. What is the equation of line dd?\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.
  1. Determine slope of line c: Determine the slope of line c. The equation of line c is given as y=−19x−10y = -\frac{1}{9}x - 10. The slope-intercept form of a line is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept. By comparing the given equation with the slope-intercept form, we can see that the slope (mm) of line c is −19-\frac{1}{9}.
  2. Determine slope of line dd: Since line dd is parallel to line cc, determine the slope of line dd. Lines that are parallel have the same slope. Therefore, the slope of line dd will be the same as the slope of line cc, which is −19-\frac{1}{9}.
  3. Use point-slope form: Use the point-slope form to find the equation of line dd. The point-slope form of a line is y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is a point on the line. We know that line dd passes through the point (−9,−7)(-9, -7) and has a slope of −19-\frac{1}{9}. Plugging these values into the point-slope form gives us: y−(−7)=−19(x−(−9))y - (-7) = -\frac{1}{9}(x - (-9))
  4. Simplify equation of line d: Simplify the equation of line d.\newliney+7=−19(x+9)y + 7 = -\frac{1}{9}(x + 9)\newliney+7=−19x−1y + 7 = -\frac{1}{9}x - 1\newlineSubtract 77 from both sides to get the equation in slope-intercept form:\newliney=−19x−1−7y = -\frac{1}{9}x - 1 - 7\newliney=−19x−8y = -\frac{1}{9}x - 8

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