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The equation of line cc is y=18x+10y = \frac{1}{8}x + 10. Line dd is perpendicular to line cc and passes through (1,1)(-1,1). What is the equation of line dd?\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.

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Q. The equation of line cc is y=18x+10y = \frac{1}{8}x + 10. Line dd is perpendicular to line cc and passes through (1,1)(-1,1). What is the equation of line dd?\newlineWrite the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.
  1. Perpendicular Lines Slopes: Line dd is perpendicular to line cc. Are their slopes the same or opposite reciprocals? Slopes of perpendicular lines are opposite reciprocals.
  2. Equation of Line c: Equation of line c: \newliney=18x+10y = \frac{1}{8}x + 10\newlineFind the slope of line c.\newlineCompare y=18x+10y = \frac{1}{8}x + 10 with y=mx+by = mx + b.\newlinem=18m = \frac{1}{8}\newlineSlope of line c: 18\frac{1}{8}
  3. Slope of Line dd: Line dd is perpendicular to cc.\newlineSlope of line cc: 18\frac{1}{8}\newlineFind the slope of line dd.\newlineOpposite reciprocal of 18\frac{1}{8} is 8-8.\newlineSlope of line dd: 8-8
  4. Y-Intercept Calculation: For line dd: \newlineSlope (mm): 8-8 \newlinePoint: (1,1)(-1, 1) \newlinePlug these values in y=mx+by = mx + b and find the y-intercept.\newline1=8(1)+b1 = -8(-1) + b \newline1=8+b1 = 8 + b\newline18=b1 - 8 = b\newline7=b-7 = b
  5. Equation of Line d: For line d: \newlineSlope mm: 8-8 \newliney-intercept bb: 7-7 \newlineWhat is the equation of the line d in slope-intercept form?\newlineSubstitute 8-8 for mm and 7-7 for bb in y=mx+by = mx + b. \newliney=8x7y = -8x - 7

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