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The distance a person can see through a particular submarine periscope is given by the equation 
d=6sqrt(h-4)+3, where 
h is the height in feet above water.

33. The distance a person can see through a particular submarine periscope is given by the equation d=6h4+3 d=6 \sqrt{h-4}+3 , where h h is the height in feet above water.

Full solution

Q. 33. The distance a person can see through a particular submarine periscope is given by the equation d=6h4+3 d=6 \sqrt{h-4}+3 , where h h is the height in feet above water.
  1. Plug in value of hh: We need to plug in the value of hh into the equation d=6h4+3d=6\sqrt{h-4}+3 to find the distance dd.\newlineCalculation: d=694+3d = 6\sqrt{9-4} + 3
  2. Simplify inside square root: Now, we simplify inside the square root first.\newlineCalculation: d=65+3d = 6\sqrt{5} + 3
  3. Multiply by 66: Next, we multiply 66 by the square root of 55.\newlineCalculation: d=6×5+3d = 6 \times \sqrt{5} + 3
  4. Calculate square root: We calculate the square root of 55 and then multiply by 66.\newlineCalculation: d=6×2.236+3d = 6 \times 2.236 + 3
  5. Do the multiplication: Now, we do the multiplication.\newlineCalculation: d=13.416+3d = 13.416 + 3
  6. Add 33 to result: Finally, we add 33 to the result.\newlineCalculation: d=16.416d = 16.416

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