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The digit in the tens place of two-digit number is three times that in the units place. If the digits are reversed, the new number will be 50,63650,636 less than the original number. Find the original number.

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Q. The digit in the tens place of two-digit number is three times that in the units place. If the digits are reversed, the new number will be 50,63650,636 less than the original number. Find the original number.
  1. Identify Units and Tens: Let the units digit be xx. Then, the tens digit is 3x3x. The original number can be expressed as 10×(3x)+x=30x+x=31x10 \times (3x) + x = 30x + x = 31x.
  2. Reverse Digits: When the digits are reversed, the number becomes 10x+3x=13x10x + 3x = 13x.
  3. Subtract Reversed Number: According to the problem, the original number minus the reversed number is 5063650636: 31x13x=5063631x - 13x = 50636.
  4. Simplify Equation: Simplify the equation: 18x=5063618x = 50636.
  5. Solve for x: Solve for x: x=5063618=2813x = \frac{50636}{18} = 2813.

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