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The country of Freedonia has decided to reduce its carbondioxide emission by 
35% each year. This year the country emitted 40 million tons of carbon-dioxide.
Write a function that gives Freedonia's carbon-dioxide emissions in million tons, 
E(t),t years from today.

E(t)=

The country of Freedonia has decided to reduce its carbondioxide emission by 35% 35 \% each year. This year the country emitted 4040 million tons of carbon-dioxide.\newlineWrite a function that gives Freedonia's carbon-dioxide emissions in million tons, E(t),t E(t), t years from today.\newlineE(t)= E(t)=\square

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Q. The country of Freedonia has decided to reduce its carbondioxide emission by 35% 35 \% each year. This year the country emitted 4040 million tons of carbon-dioxide.\newlineWrite a function that gives Freedonia's carbon-dioxide emissions in million tons, E(t),t E(t), t years from today.\newlineE(t)= E(t)=\square
  1. Understand Exponential Decay: To create a function that models the carbon-dioxide emissions in Freedonia tt years from today, we need to understand that a reduction of 35%35\% each year means that each year, Freedonia will emit only 65%65\% (100%35%100\% - 35\%) of the carbon-dioxide it emitted the previous year. This is an example of exponential decay, and the general formula for exponential decay is:\newlineE(t)=E0×(1r)tE(t) = E_0 \times (1 - r)^t\newlinewhere:\newlineE(t)E(t) is the amount after tt years,\newlineE0E_0 is the initial amount (the amount today),\newlinerr is the decay rate (as a decimal), and\newlinett is the time in years.\newlineGiven that the initial amount of carbon-dioxide is 35%35\%00 million tons and the decay rate is 35%35\%, or 35%35\%22 as a decimal, we can substitute these values into the formula.
  2. Convert Percentage to Decimal: First, we convert the percentage reduction to a decimal by dividing by 100100. So, 35%35\% becomes 0.350.35.\newlineNext, we subtract this decimal from 11 to find the percentage that remains each year. This gives us 10.35=0.651 - 0.35 = 0.65.\newlineNow we can write the function for E(t)E(t) using the initial amount of carbon-dioxide, which is 4040 million tons, and the decay factor, which is 0.650.65.\newlineE(t)=40×(0.65)tE(t) = 40 \times (0.65)^t
  3. Write Emission Function: The function E(t)=40×(0.65)tE(t) = 40 \times (0.65)^t now represents the carbon-dioxide emissions in million tons, tt years from today. This function can be used to calculate the emissions for any given year tt by substituting the value of tt into the function.\newlineTo check for any mathematical errors, let's consider the case when t=0t = 0, which should give us the initial value of 4040 million tons.\newlineE(0)=40×(0.65)0=40×1=40E(0) = 40 \times (0.65)^0 = 40 \times 1 = 40\newlineSince any number to the power of 00 is 11, and 4040 times 11 is 4040, the function checks out for t=0t = 0.

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