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The conical tank shown here is filled with olive oil weighing 
41lb//ft^(3). How much work does it take to pump all of the oil to the rim of the tank?

W= 
◻ 
ft-lb (Round to the nearest whole number as needed.)

The conical tank shown here is filled with olive oil weighing 41lb/ft3 41 \mathrm{lb} / \mathrm{ft}^{3} . How much work does it take to pump all of the oil to the rim of the tank?\newlineW= W= \square ftlb \mathrm{ft}-\mathrm{lb} (Round to the nearest whole number as needed.)

Full solution

Q. The conical tank shown here is filled with olive oil weighing 41lb/ft3 41 \mathrm{lb} / \mathrm{ft}^{3} . How much work does it take to pump all of the oil to the rim of the tank?\newlineW= W= \square ftlb \mathrm{ft}-\mathrm{lb} (Round to the nearest whole number as needed.)
  1. Find Volume of Tank: First, we need to find the volume of the conical tank to determine how much oil it holds. Assume the tank has a height hh and a radius rr at the top. The formula for the volume of a cone is V=13πr2hV = \frac{1}{3}\pi r^2 h.
  2. Calculate Weight of Oil: Next, calculate the weight of the olive oil in the tank. Given the density of olive oil is 41lb/ft341 \, \text{lb/ft}^3, multiply this by the volume of the tank to find the total weight. Weight = Density ×\times Volume = 41lb/ft3×V41 \, \text{lb/ft}^3 \times V.
  3. Calculate Work Done: To find the work done to pump the oil to the rim, use the work formula W=Weight×DistanceW = \text{Weight} \times \text{Distance}. Here, the distance is the height of the tank, hh, since we're pumping to the rim. W=41V×hW = 41V \times h.

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