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The community garden club has a vegetable garden that measures 
15m by 
30m. One of the members has donated a new piece of land for a larger garden. They plan to increase the garden by 
250m^(2). However, because of the dimensions of the new land, both dimensions of the original garden must be increased by the same amount. Determine the dimensions of the new garden.


" [20 m "35m" ] "

88. The community garden club has a vegetable garden that measures 15 m 15 \mathrm{~m} by 30 m 30 \mathrm{~m} . One of the members has donated a new piece of land for a larger garden. They plan to increase the garden by 250 m2 250 \mathrm{~m}^{2} . However, because of the dimensions of the new land, both dimensions of the original garden must be increased by the same amount. Determine the dimensions of the new garden.\newline [20 m 35 m ]  \text { [20 m } 35 \mathrm{~m} \text { ] }

Full solution

Q. 88. The community garden club has a vegetable garden that measures 15 m 15 \mathrm{~m} by 30 m 30 \mathrm{~m} . One of the members has donated a new piece of land for a larger garden. They plan to increase the garden by 250 m2 250 \mathrm{~m}^{2} . However, because of the dimensions of the new land, both dimensions of the original garden must be increased by the same amount. Determine the dimensions of the new garden.\newline [20 m 35 m ]  \text { [20 m } 35 \mathrm{~m} \text { ] }
  1. Calculate Original Area: The original area of the garden is 15m15\,\text{m} by 30m30\,\text{m}, so the original area is 15m×30m15\,\text{m} \times 30\,\text{m}.\newlineCalculate the original area: 15m×30m=450m215\,\text{m} \times 30\,\text{m} = 450\,\text{m}^2.
  2. Calculate New Area: The new area will be the original area plus the increase of 250m2250\,\text{m}^2.\newlineCalculate the new area: 450m2+250m2=700m2450\,\text{m}^2 + 250\,\text{m}^2 = 700\,\text{m}^2.
  3. Write Equation for New Area: Let xx be the amount by which each dimension is increased. The new dimensions will be (15m+x)(15m + x) and (30m+x)(30m + x). Write the equation for the new area: (15m+x)(30m+x)=700m2(15m + x)(30m + x) = 700m^2.
  4. Expand and Simplify Equation: Expand the equation: 450m2+15mx+30mx+x2=700m2450m^2 + 15mx + 30mx + x^2 = 700m^2. Simplify the equation: x2+45mx250m2=0x^2 + 45mx - 250m^2 = 0.
  5. Use Quadratic Formula: Use the quadratic formula to solve for xx: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where a=1a = 1, b=45mb = 45m, and c=250m2c = -250m^2. Calculate the discriminant: (45m)24(1)(250m2)=2025m2+1000m2=3025m2(45m)^2 - 4(1)(-250m^2) = 2025m^2 + 1000m^2 = 3025m^2.
  6. Calculate Discriminant: Calculate the square root of the discriminant: 3025m2=55m\sqrt{3025m^2} = 55m.\newlinePlug into the quadratic formula: x=45m±55m2x = \frac{-45m \pm 55m}{2}.
  7. Calculate Square Root: There are two possible solutions for xx: x=5mx = 5m or x=50mx = -50m. Since a negative increase in dimensions doesn't make sense, we discard x=50mx = -50m.
  8. Find Possible Solutions: The increase in each dimension is 5m5\,\text{m}. So the new dimensions are 15m+5m15\,\text{m} + 5\,\text{m} and 30m+5m30\,\text{m} + 5\,\text{m}. Calculate the new dimensions: 20m20\,\text{m} and 35m35\,\text{m}.

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