The average amount of money spent for lunch per person in the college cafeteria is $7.15 and the standard deviation is $2.48. Suppose that 48 randomly selected lunch patrons are observed. Assume the distribution of money spent is normal, and round all answers to 4 decimal places where possible. What is the distribution of X? X∼N(,) What is the distribution of xˉ? xˉ∼N(,) For a single randomly selected lunch patron, find the probability that this patron's lunch cost is between $6.77 and $7.27. For the group of 48 patrons, find the probability that the average lunch cost is between $6.77 and $7.27. HINTS: $2.480$2.481 To find $2.482 use normalcdf$2.483$2.484$2.485 When you are looking for the probability of one value the $2.486 Submit
Q. The average amount of money spent for lunch per person in the college cafeteria is $7.15 and the standard deviation is $2.48. Suppose that 48 randomly selected lunch patrons are observed. Assume the distribution of money spent is normal, and round all answers to 4 decimal places where possible. What is the distribution of X? X∼N(,) What is the distribution of xˉ? xˉ∼N(,) For a single randomly selected lunch patron, find the probability that this patron's lunch cost is between $6.77 and $7.27. For the group of 48 patrons, find the probability that the average lunch cost is between $6.77 and $7.27. HINTS: $2.480$2.481 To find $2.482 use normalcdf$2.483$2.484$2.485 When you are looking for the probability of one value the $2.486 Submit
Given Data: Given μ=$7.15 and σ=$2.48. For a single lunch patron, the distribution of X is X∼N(μ,σ).
Distribution of X: So, X∼N(7.15,2.48).
Distribution of xˉ: For the average of 48 patrons, the distribution of xˉ is xˉ∼N(μ,σ/n).
Calculate σ/n: Calculate σ/n where n=48.σ/n=2.48/48≈2.48/6.9282≈0.3578.
Probability Calculation: So, xˉ∼N(7.15,0.3578).
Use normalcdf: To find the probability that a single patron's lunch cost is between $6.77 and $7.27, use P(6.77<X<7.27).
Calculate Probability: Use normalcdf for a single value with n=1.P(6.77<X<7.27)=normalcdf(6.77,7.27,7.15,2.48).
Calculate Probability: Use normalcdf for a single value with n=1.P(6.77<X<7.27)=normalcdf(6.77,7.27,7.15,2.48).Calculate the probability for a single patron.P(6.77<X<7.27)≈normalcdf(6.77,7.27,7.15,2.48)≈0.1574.