Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

TEST COMPETITION

The mobile system in the Figure is in the equilibrium condition. The object of
m_(A) has a mass of
0.5kg and hang at the first crossbar. The second crossbar supports the mass of
m_(B) and
m_(C). Determine the tension
F at the first crossbar and the masses of the objects
m_(B) and
m_(C) by neglecting the weights of crossbars.
(g=9.8(m)//s^(2):} ).

TEST COMPETITION $\newline$ The mobile system in the Figure is in the equilibrium condition. The object of $m_{A}$ has a mass of $0.5\,\text{kg}$ and hang at the first crossbar. The second crossbar supports the mass of $m_{B}$ and $m_{C}$ . Determine the tension $F$ at the first crossbar and the masses of the objects $m_{B}$ and $m_{C}$ by neglecting the weights of crossbars. $(g=9.8\,\text{m}/\text{s}^{2})$ .

View step-by-step help

View step-by-step help

Interpret functions using everyday language

Full solution

Q. TEST COMPETITION

\newline

The mobile system in the Figure is in the equilibrium condition. The object of

m_{A}

has a mass of

0.5\,\text{kg}

and hang at the first crossbar. The second crossbar supports the mass of

m_{B}

and

m_{C}

. Determine the tension

F

at the first crossbar and the masses of the objects

m_{B}

and

m_{C}

by neglecting the weights of crossbars.

(g=9.8\,\text{m}/\text{s}^{2})

.

Analyze and apply equilibrium condition: Analyze the problem and apply the equilibrium condition for the first crossbar. Since the system is in equilibrium, the total force acting on the crossbar must be zero. This includes the gravitational force due to the mass $m_{A}$ and the tension $F$ in the crossbar.
Apply equilibrium condition to second crossbar: Apply the equilibrium condition to the second crossbar. The tension $F$ from the first crossbar acts upwards on the second crossbar, and the gravitational forces due to $m_{B}$ and $m_{C}$ act downwards.
Solve for $m_B$ and $m_C$ : Solve for $m_B$ and $m_C$ . We know $F = 4.9 \, \text{N}$ from the first crossbar.

More problems from Interpret functions using everyday language

Question

Which of the following numbers are less than

-0

625

\newline

Choose all answers that apply:

\newline

-\frac{8}{5}

\newline

-\frac{5}{8}

\newline

-0

5

Posted 3 months ago

Question

For each of the following rational expressions, determine the values for which the expression is undefined:

\newline

A) The expression

\newline

(\frac{14m}{8n})

is undefined when

\newline

\hat{0}=

\newline

B) The expression

\newline

(\frac{19y+5}{20y-20})

is undefined when ?

\newline

\hat{0}=

\newline

C) The expression

\newline

(\frac{b-16}{b^{2}-361})

is undefined when ?

\newline

\hat{0}=

Posted 2 months ago

Question

Use the following function rule to find

f(5)

\newline

f(x) = \frac{x}{5}

\newline

f(5) =

Posted 2 months ago

Question

Use the following function rule to find

f(10)

\newline

f(x) = 2 + \frac{x}{10}

\newline

f(10) =

Posted 2 months ago

Question

r

of a sphere is increasing at the uniform rate of

0.3\,\text{cm}

per second. At the instant when the surface area

S

100\pi\,\text{cm}^{2}

, what is the rate of increase, in

\text{cm}^{3}

per second, in the volume

V

(S=4\pi r^{2})

(V=\frac{4}{3}\pi r^{3})

\newline

10\pi

\newline

12\pi

\newline

0.3\,\text{cm}

0

\newline

0.3\,\text{cm}

1

Posted 2 months ago

Question

Diane is making fancy headbands to sell at a craft fair. The number of headbands she can make is limited by the amount of ribbon she has on hand.

\newline

h =

the number of headbands Diane can make

\newline

r =

the amount of ribbon Diane has on hand

\newline

Which of the variables is independent and which is dependent?

\newline

\newline

h

is the independent variable and

r

is the dependent variable

\newline

r

is the independent variable and

h

is the dependent variable

Posted 2 months ago

Question

Use the following function rule to find

f(41)

\newline

f(x) = 7\sqrt{x + 8}

\newline

f(41) =

Posted 2 months ago

Question

Use the following function rule to find

f(115)

\newline

f(x) = 4\sqrt{x - 99}

\newline

f(115) =

Posted 2 months ago

Question

Use the following function rule to find

f(5)

\newline

f(x) = 12\sqrt{95 + x}

\newline

f(5) =

Posted 2 months ago

Question

Use the following function rule to find

f(81)

\newline

f(x) = 9\sqrt{x}

\newline

f(81) =

Posted 2 months ago