Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Terrell has 34 fewer sand dollars than Logan, They have 66 sand dollars together. How many sand dollars are in Terrells collection? How many sand dollars are in Logan's collection?
Select the person with moce sand dollars: Logan
Select, a label for each bar, Drag the bars to the right to draw a model that represents the scenario.

Terrell has 3434 fewer sand dollars than Logan, They have 6666 sand dollars together. How many sand dollars are in Terrells collection? How many sand dollars are in Logan's collection?\newlineSelect the person with moce sand dollars: Logan\newlineSelect, a label for each bar, Drag the bars to the right to draw a model that represents the scenario.

Full solution

Q. Terrell has 3434 fewer sand dollars than Logan, They have 6666 sand dollars together. How many sand dollars are in Terrells collection? How many sand dollars are in Logan's collection?\newlineSelect the person with moce sand dollars: Logan\newlineSelect, a label for each bar, Drag the bars to the right to draw a model that represents the scenario.
  1. Define Variables: Let's define the number of sand dollars Terrell has as TT and the number Logan has as LL. We are given that Terrell has 3434 fewer sand dollars than Logan, which can be written as:\newlineT=L34T = L - 34
  2. Total Sand Dollars: We also know that together they have 6666 sand dollars, which can be written as:\newlineT+L=66T + L = 66
  3. Substitute and Solve: Now we have a system of two equations:\newline11) T=L34T = L - 34\newline22) T+L=66T + L = 66\newlineWe can substitute the expression for TT from the first equation into the second equation to find the value of LL.\newline(L34)+L=66(L - 34) + L = 66
  4. Combine Like Terms: Combine like terms in the equation: 2L34=662L - 34 = 66
  5. Isolate Term: Add 3434 to both sides of the equation to isolate the term with LL: \newline2L34+34=66+342L - 34 + 34 = 66 + 34\newline2L=1002L = 100
  6. Solve for L: Divide both sides of the equation by 22 to solve for L:\newline2L2=1002\frac{2L}{2} = \frac{100}{2}\newlineL=50L = 50
  7. Substitute Back: Now that we know the value of LL, we can substitute it back into the first equation to find the value of TT:
    T=L34T = L - 34
    T=5034T = 50 - 34
    T=16T = 16

More problems from The Central Limit Theorem