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Teresa is maintaining a camp fire. She can keep the fire burning for 4 hours with 6 logs. She wants to know how many logs 
(y) she needs to keep the fire burning for 18 hours. She assumes all logs are the same.
How many logs does Teresa need to maintain the fire for 18 hours?

◻ logs

Teresa is maintaining a camp fire. She can keep the fire burning for 44 hours with 66 logs. She wants to know how many logs (y) (y) she needs to keep the fire burning for 1818 hours. She assumes all logs are the same.\newlineHow many logs does Teresa need to maintain the fire for 1818 hours?\newline \square logs

Full solution

Q. Teresa is maintaining a camp fire. She can keep the fire burning for 44 hours with 66 logs. She wants to know how many logs (y) (y) she needs to keep the fire burning for 1818 hours. She assumes all logs are the same.\newlineHow many logs does Teresa need to maintain the fire for 1818 hours?\newline \square logs
  1. Calculate Logs per Hour: Find out how many logs are used per hour. 66 logs for 44 hours means 6 logs4 hours=1.5\frac{6 \text{ logs}}{4 \text{ hours}} = 1.5 logs per hour.
  2. Total Logs for 1818 Hours: Calculate the total logs needed for 1818 hours. 1.5 logs/hour×18 hours=27 logs.1.5 \text{ logs/hour} \times 18 \text{ hours} = 27 \text{ logs}.

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