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tan 2u=(2cot u)/(csc^(2)u-2)

tan2u=2cotucsc2u2 \tan 2 u=\frac{2 \cot u}{\csc ^{2} u-2}

Full solution

Q. tan2u=2cotucsc2u2 \tan 2 u=\frac{2 \cot u}{\csc ^{2} u-2}
  1. Recall Identities: Recall the trigonometric identities: cotu=1tanu\cot u = \frac{1}{\tan u} and cscu=1sinu.\csc u = \frac{1}{\sin u}.
  2. Rewrite Equation: Rewrite the equation using the identities: tan2u=2×(1tanu)(1sinu)22\tan 2u = \frac{2 \times \left(\frac{1}{\tan u}\right)}{\left(\frac{1}{\sin u}\right)^{2} - 2}.
  3. Simplify Equation: Simplify the equation: tan2u=2/tanu(1/sin2u)2\tan 2u = \frac{2/\tan u}{(1/\sin^{2}u) - 2}.
  4. Convert to sin/cos: Convert tanu\tan u to sinu\sin u and cosu\cos u: tan2u=2×(cosusinu)(1sin2u)2\tan 2u = \frac{2 \times \left(\frac{\cos u}{\sin u}\right)}{\left(\frac{1}{\sin^{2}u}\right) - 2}.
  5. Clear Fractions: Multiply both numerator and denominator by sin2u\sin^{2}u to clear the fraction: tan2u=2×(cosu/sinu)×sin2u12sin2u\tan 2u = \frac{2 \times (\cos u/\sin u) \times \sin^{2}u}{1 - 2\sin^{2}u}.
  6. Use Double Angle Identity: Simplify the equation: tan2u=2cosusinu12sin2u.\tan 2u = \frac{2\cos u \cdot \sin u}{1 - 2\sin^{2}u}.
  7. Substitute sin(2u)\sin(2u): Use the double angle identity for sine: sin(2u)=2sinucosu\sin(2u) = 2\sin u \cdot \cos u.
  8. Use Pythagorean Identity: Substitute sin(2u)\sin(2u) into the equation: tan2u=sin(2u)(12sin2u)\tan 2u = \frac{\sin(2u)}{(1 - 2\sin^{2}u)}.
  9. Find cos2u\cos^2 u: Use the Pythagorean identity: sin2u+cos2u=1\sin^2 u + \cos^2 u = 1.
  10. Substitute cos2u\cos^2 u: Rearrange the identity to find cos2u\cos^2 u: cos2u=1sin2u\cos^2 u = 1 - \sin^2 u.
  11. Final Simplification: Substitute cos2u\cos^2 u into the equation: tan2u=sin(2u)12(1cos2u)\tan 2u = \frac{\sin(2u)}{1 - 2(1 - \cos^2 u)}.
  12. Use Double Angle Identity: Simplify the equation: tan2u=sin(2u)2cos2u1.\tan 2u = \frac{\sin(2u)}{2\cos^{2}u - 1}.
  13. Recognize Mistake: Use the double angle identity for cosine: cos(2u)=2cos2(u)1\cos(2u) = 2\cos^2(u) - 1.
  14. Recognize Mistake: Use the double angle identity for cosine: cos(2u)=2cos2(u)1\cos(2u) = 2\cos^2(u) - 1. Substitute cos(2u)\cos(2u) into the equation: tan2u=sin(2u)cos(2u)\tan 2u = \frac{\sin(2u)}{\cos(2u)}.
  15. Recognize Mistake: Use the double angle identity for cosine: cos(2u)=2cos2(u)1\cos(2u) = 2\cos^2(u) - 1.Substitute cos(2u)\cos(2u) into the equation: tan2u=sin(2u)cos(2u)\tan 2u = \frac{\sin(2u)}{\cos(2u)}.Recognize that tan2u=sin(2u)cos(2u)\tan 2u = \frac{\sin(2u)}{\cos(2u)} is the definition of tangent: tan2u=tan(2u)\tan 2u = \tan(2u).
  16. Recognize Mistake: Use the double angle identity for cosine: cos(2u)=2cos2(u)1\cos(2u) = 2\cos^2(u) - 1. Substitute cos(2u)\cos(2u) into the equation: tan2u=sin(2u)cos(2u)\tan 2u = \frac{\sin(2u)}{\cos(2u)}. Recognize that tan2u=sin(2u)cos(2u)\tan 2u = \frac{\sin(2u)}{\cos(2u)} is the definition of tangent: tan2u=tan(2u)\tan 2u = \tan(2u). Realize that we've made a mistake in the simplification process; the correct simplification should have led to tan2u=tan(2u)\tan 2u = \tan(2u) directly, without the intermediate steps.

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