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Systems by Substitution
Clark spent a total of 
$46 on a pair of shoes and a new jacket. The shoes cost 
$8 more than the jacket. Write a system of equations to represent the situation. Then find the cost of each irem.

Systems by Substitution\newlineClark spent a total of $46 \$ 46 on a pair of shoes and a new jacket. The shoes cost $8 \$ 8 more than the jacket. Write a system of equations to represent the situation. Then find the cost of each irem.

Full solution

Q. Systems by Substitution\newlineClark spent a total of $46 \$ 46 on a pair of shoes and a new jacket. The shoes cost $8 \$ 8 more than the jacket. Write a system of equations to represent the situation. Then find the cost of each irem.
  1. Identify Variables: Identify the variables for the cost of the shoes and the jacket.\newlineLet's denote the cost of the jacket as 'j ext{ dollars} ext{.} ext{ }According ext{ }to ext{ }the ext{ }problem, ext{ }the ext{ }shoes ext{ }cost ext{ } ext{\$}\(8 ext{ }more ext{ }than ext{ }the ext{ }jacket, ext{ }so ext{ }the ext{ }cost ext{ }of ext{ }the ext{ }shoes ext{ }will ext{ }be ext{ }' ext{ }j ext{ }+ ext{ }88 ext{ }' ext{ }dollars ext{.} ext{ }
  2. Write First Equation: Write the first equation representing the total cost.\newlineThe total cost of the shoes and the jacket is $46\$46. So, the first equation is:\newlinej+(j+8)=46j + (j + 8) = 46
  3. Write Second Equation: Write the second equation representing the relationship between the cost of the shoes and the jacket.\newlineThe second equation is already given by the problem: the shoes cost $8\$8 more than the jacket. This is represented by the equation:\newlineshoes=jacket+8\text{shoes} = \text{jacket} + 8\newlineSince we've already defined the cost of the shoes as 'j+8j + 8', this equation is not needed as a separate equation in the system.
  4. Combine and Solve: Combine the terms in the first equation and solve for jj.j+j+8=46j + j + 8 = 462j+8=462j + 8 = 46
  5. Isolate 'j': Subtract 88 from both sides of the equation to isolate the term with 'j'.\newline2j+88=4682j + 8 - 8 = 46 - 8\newline2j=382j = 38
  6. Solve for 'j': Divide both sides of the equation by 22 to solve for 'j'.\newline2j2=382\frac{2j}{2} = \frac{38}{2}\newlinej=19j = 19
  7. Calculate Shoes Cost: Calculate the cost of the shoes using the value of ' extit{j}'.\newlineSince the shoes cost $\$88 more than the jacket, and we've found that the jacket costs $\$1919, the shoes cost:\newlineshoes = j+8j + 8\newlineshoes = 19+819 + 8\newlineshoes = 2727
  8. Check Solution: Check the solution by substituting the values back into the original equation.\newlinej+(j+8)=46j + (j + 8) = 46\newline19+(19+8)=4619 + (19 + 8) = 46\newline19+27=4619 + 27 = 46\newline46=4646 = 46\newlineThe solution checks out.

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