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Suppose that zz varies jointly with the cube of xx and the square of yy. Find the constant of proportionality kk if z=3600z = 3600 when y=3y = 3 and x=5x =5.

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Q. Suppose that zz varies jointly with the cube of xx and the square of yy. Find the constant of proportionality kk if z=3600z = 3600 when y=3y = 3 and x=5x =5.
  1. Identify general form: Identify the general form of joint variation.\newlineJoint variation is expressed as z=k×xn×ymz = k \times x^n \times y^m, where kk is the constant of proportionality, and nn and mm are the powers to which xx and yy are raised, respectively. In this case, since zz varies jointly with the cube of xx and the square of yy, the equation becomes z=k×x3×y2z = k \times x^3 \times y^2.
  2. Substitute values into equation: Substitute z=3600z = 3600, y=3y = 3, and x=5x = 5 into the joint variation equation z=k×x3×y2z = k \times x^3 \times y^2.\newline3600=k×53×323600 = k \times 5^3 \times 3^2
  3. Calculate x3x^3 and y2y^2: Calculate the values of x3x^3 and y2y^2.\newline53=5×5×5=1255^3 = 5 \times 5 \times 5 = 125\newline32=3×3=93^2 = 3 \times 3 = 9
  4. Substitute calculated values: Substitute the calculated values into the equation. \newline3600=k×125×93600 = k \times 125 \times 9
  5. Solve for constant of proportionality: Solve the equation for the constant of proportionality, kk.3600=k×(125×9)3600 = k \times (125 \times 9)3600=k×11253600 = k \times 1125k=36001125k = \frac{3600}{1125}
  6. Perform division: Perform the division to find the value of kk.k=36001125k = \frac{3600}{1125}k=3.2k = 3.2

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