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sum_(y=1)^(2)(1-y)=

$\sum_{y=1}^{2}(1-y)=$

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Find derivatives using the chain rule I

Full solution

Q.

\sum_{y=1}^{2}(1-y)=

Define Series: The series is a finite series with two terms, corresponding to $y=1$ and $y=2$ . We will evaluate the expression $(1-y)$ for each value of $y$ and then sum the results.
Evaluate $y=1$ : First, we substitute $y=1$ into the expression $(1-y)$ to get the first term of the series. This gives us $1 - 1 = 0$ .
Evaluate $y=2$ : Next, we substitute $y=2$ into the expression $(1-y)$ to get the second term of the series. This gives us $1 - 2 = -1$ .
Sum Terms: Now, we add the two terms of the series together. The sum is $0 + (-1) = -1$ .

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