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sum_(n=0)^(2)(-n)=

$\sum_{n=0}^{2}(-n)=$

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Find derivatives using the chain rule I

Full solution

Q.

\sum_{n=0}^{2}(-n)=

Arithmetic series calculation: The series is a finite arithmetic series where each term is the negative of the index $n$ . We will calculate each term and add them together.
First term calculation: First term: when $n=0$ , the term is $(-0)$ which equals $0$ .
Second term calculation: Second term: when $n=1$ , the term is $(-1)$ which equals $-1$ .
Third term calculation: Third term: when $n=2$ , the term is $(-2)$ which equals $-2$ .
Sum calculation: Now, we add all the terms together: $0 + (-1) + (-2)$ .
Final result: The sum is $0 - 1 - 2$ , which equals $-3$ .

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