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sum_(n=0)^(2)(n)=

n=02(n)= \sum_{n=0}^{2}(n)=

Full solution

Q. n=02(n)= \sum_{n=0}^{2}(n)=
  1. Question Prompt: The question_prompt: What is the sum of the series from n=0n=0 to n=2n=2 of the term nn?
  2. Evaluate Terms: To find the sum of the series, we simply need to evaluate the expression for each value of nn from 00 to 22 and then add the results together.
  3. Substitute n=0n=0: First, we substitute n=0n=0 into the term nn.\newlineSum when n=0n=0: 00
  4. Substitute n=1n=1: Next, we substitute n=1n=1 into the term nn.
    Sum when n=1n=1: 0+1=10 + 1 = 1
  5. Substitute n=2n=2: Finally, we substitute n=2n=2 into the term nn.\newlineSum when n=2n=2: 1+2=31 + 2 = 3
  6. Calculate Total Sum: Adding all these sums together gives us the total sum of the series from n=0n=0 to n=2n=2.\newlineTotal sum: 0+1+2=30 + 1 + 2 = 3

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