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sum_(k=1)^(3)(k-4)=

k=13(k4)= \sum_{k=1}^{3}(k-4)=

Full solution

Q. k=13(k4)= \sum_{k=1}^{3}(k-4)=
  1. Arithmetic series definition: The series is a simple arithmetic series where each term is given by k4k-4. We will evaluate each term separately and then sum them up.
  2. First term calculation: First term when k=1k=1: (14)=3(1-4) = -3.
  3. Second term calculation: Second term when k=2k=2: (24)=2(2-4) = -2.
  4. Third term calculation: Third term when k=3k=3: (34)=1(3-4) = -1.
  5. Summing up the terms: Now, we sum up all the terms: (3)+(2)+(1)(-3) + (-2) + (-1).
  6. Calculating the sum: Calculating the sum: 321=6-3 - 2 - 1 = -6.

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