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sum_(k=0)^(1)(2k-1)=

k=01(2k1)= \sum_{k=0}^{1}(2 k-1)=

Full solution

Q. k=01(2k1)= \sum_{k=0}^{1}(2 k-1)=
  1. Term Calculation for k=0k=0: The series is a finite sum with terms defined by the expression (2k1)(2k-1) for each integer value of kk from 00 to 11. We will calculate each term separately and then add them together.
  2. Term Calculation for k=1k=1: First, we calculate the term for k=0k=0. Substituting k=0k=0 into the expression (2k1)(2k-1) gives us (2×01)(2\times 0-1), which simplifies to 1-1.
  3. Sum of Terms for k=0k=0 and k=1k=1: Next, we calculate the term for k=1k=1. Substituting k=1k=1 into the expression (2k1)(2k-1) gives us (2×11)(2\times 1-1), which simplifies to 11.
  4. Simplified Sum: Now, we add the two terms together. The sum of the terms for k=0k=0 and k=1k=1 is (1)+(1)(-1) + (1).
  5. Simplified Sum: Now, we add the two terms together. The sum of the terms for k=0k=0 and k=1k=1 is (1)+(1)(-1) + (1). The sum (1)+(1)(-1) + (1) simplifies to 00.

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