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sum_(j=1)^(3)(3j)=

j=13(3j)= \sum_{j=1}^{3}(3 j)=

Full solution

Q. j=13(3j)= \sum_{j=1}^{3}(3 j)=
  1. Calculate first term: The series is an arithmetic series where each term is given by the formula 3j3j. We need to calculate the sum of the first three terms of this series: 3(1)+3(2)+3(3)3(1) + 3(2) + 3(3).
  2. Calculate second term: Calculate the first term: 3(1)=33(1) = 3.
  3. Calculate third term: Calculate the second term: 3(2)=63(2) = 6.
  4. Calculate sum of series: Calculate the third term: 3(3)=93(3) = 9.
  5. Calculate sum of series: Calculate the third term: 3(3)=93(3) = 9. Add the three terms together to find the sum of the series: 3+6+9=183 + 6 + 9 = 18.

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