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sum_(j=0)^(2)(j^(2))=

$\sum_{j=0}^{2}\left(j^{2}\right)=$

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Find derivatives using the chain rule I

Full solution

Q.

\sum_{j=0}^{2}\left(j^{2}\right)=

Problem Statement: The problem asks for the sum of the squares of the integers from $0$ to $2$ . This can be written as the sum of $j^2$ where $j$ ranges from $0$ to $2$ .
Calculate Square of First Integer: First, calculate the square of the first integer, which is $0$ . The square of $0$ is $0^2 = 0$ .
Calculate Square of Second Integer: Next, calculate the square of the second integer, which is $1$ . The square of $1$ is $1^2 = 1$ .
Calculate Square of Third Integer: Finally, calculate the square of the third integer, which is $2$ . The square of $2$ is $2^2 = 4$ .
Sum of Squares: Now, sum the squares of these integers: $0 + 1 + 4$ .
Final Result: The sum is $0 + 1 + 4 = 5$ .

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