Q. Subtract −3c2+12cd−4d2 from 4c2+3cd+2d2. Your answer should be a polynomial in standard form.
Write Polynomials to Subtract: Write down the polynomials that need to be subtracted.We have the first polynomial 4c2+3cd+2d2 and we need to subtract the second polynomial −3c2+12cd−4d2 from it.
Change Signs of Second Polynomial: Change the signs of the second polynomial before subtracting.To subtract the second polynomial, we need to change the signs of all its terms and then add it to the first polynomial.So, −3c2 becomes +3c2, 12cd becomes −12cd, and −4d2 becomes +4d2.
Add Corresponding Terms: Add the corresponding terms of the resulting polynomials.Now, we combine like terms from the first polynomial and the sign-changed second polynomial.(4c2+3cd+2d2)+(3c2−12cd+4d2)
Perform Addition: Perform the addition.Add the c2 terms: 4c2+3c2=7c2Add the cd terms: 3cd−12cd=−9cdAdd the d2 terms: 2d2+4d2=6d2
Write Final Answer: Write the final answer in standard form.The resulting polynomial in standard form is:7c2−9cd+6d2
More problems from Composition of linear functions: find an equation