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State all integer values of
x in the interval
-8 <= x <= -3 that satisfy the following inequality:

2x+10 < -4
Answer:
x=

State all integer values of $x$ in the interval $-8 \leq x \leq-3$ that satisfy the following inequality: $\newline$ $2 x+10<-4$ $\newline$ Answer: $x=$

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Evaluate powers with negative or zero exponents

Full solution

Q. State all integer values of

x

in the interval

-8 \leq x \leq-3

that satisfy the following inequality:

\newline

2 x+10<-4

\newline

Answer:

x=

Identify Inequality & Interval: Identify the inequality and the given interval. $\newline$ The inequality to solve is $2x + 10 < -4$ , and we are looking for integer solutions within the interval $-8 \leq x \leq -3$ .
Isolate Variable $x$ : Isolate the variable $x$ on one side of the inequality. $\newline$ Subtract $10$ from both sides of the inequality to get $2x < -14$ . $\newline$ Calculation: $2x + 10 - 10 < -4 - 10$ $\newline$ $2x < -14$
Divide by $2$ : Divide both sides of the inequality by $2$ to solve for $x$ . $\newline$ Calculation: $\frac{2x}{2} < \frac{-14}{2}$ $\newline$ $x < -7$
Determine Integer Values: Determine the integer values of $x$ that are less than $-7$ and within the given interval $-8 \leq x \leq -3$ . Since $x$ must be less than $-7$ , the only integer value of $x$ within the interval that satisfies this condition is $x = -8$ .

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