Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

sqrt8(2sqrt2+8)
Which of the following is equivalent to the given expression?
Choose 1 answer:
(A) 16
(B) 40
(C) 
8+16sqrt2
(D) 
32+8sqrt8

8(22+8) \sqrt{8}(2 \sqrt{2}+8) \newlineWhich of the following is equivalent to the given expression?\newlineChoose 11 answer:\newline(A) 1616\newline(B) 4040\newline(C) 8+162 8+16 \sqrt{2} \newline(D) 32+88 32+8 \sqrt{8}

Full solution

Q. 8(22+8) \sqrt{8}(2 \sqrt{2}+8) \newlineWhich of the following is equivalent to the given expression?\newlineChoose 11 answer:\newline(A) 1616\newline(B) 4040\newline(C) 8+162 8+16 \sqrt{2} \newline(D) 32+88 32+8 \sqrt{8}
  1. Simplify expression inside parentheses: First, we will simplify the expression inside the parentheses by multiplying the square root of 88 with each term inside the parentheses. The expression is 8(22+8)\sqrt{8}(2\sqrt{2}+8).
  2. Calculate first term: We calculate the first term by multiplying 8\sqrt{8} with 222\sqrt{2}, which gives us 2×8×22 \times \sqrt{8} \times \sqrt{2}. Since 8=4×2=4×2=22\sqrt{8} = \sqrt{4\times2} = \sqrt{4}\times\sqrt{2} = 2\sqrt{2}, we can simplify the expression to 2×22×22 \times 2\sqrt{2} \times \sqrt{2}.
  3. Simplify first term: We know that 2×2=2\sqrt{2} \times \sqrt{2} = 2. So, the first term becomes 2×2×22 \times 2 \times 2, which equals 88.
  4. Calculate second term: Now, we calculate the second term by multiplying 8\sqrt{8} with 88. Since we already know that 8=22\sqrt{8} = 2\sqrt{2}, the second term becomes 22×82\sqrt{2} \times 8.
  5. Multiply second term: Multiplying 222\sqrt{2} by 88 gives us 16216\sqrt{2}. So, the second term is 16216\sqrt{2}.
  6. Add the two terms: Adding the two terms together, we get 8+1628 + 16\sqrt{2}. This is the simplified form of the original expression.
  7. Compare with answer choices: Comparing the simplified expression with the answer choices, we find that it matches with option (C) 8+1628+16\sqrt{2}.

More problems from Is (x, y) a solution to the system of equations?