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sqrt(y^(2))
zy

{:[48=z(z+12)],[48=z^(2)+62 z],[0=z^(2)+12 z-408],[0=3.2)(z-15.2)],[(z=-3.2quad z=15.2]:}
Find the diameter of 
o.O. A line that appears to be tangent is tangent. If your answer is not a whole number, round to the nearest tenth.
10.
11.
12.
12.5

0=36

0=8.

y2\sqrt{y^{2}}zyzy\left\{\begin{array}{l}48=z(z+12)\48=z^{2}+62z\0=z^{2}+12z-408\0=3.2)(z-15.2)\$z=-3.2\quad z=15.2\end{array}\right. Find the diameter of o.O. A line that appears to be tangent is tangent. If your answer is not a whole number, round to the nearest tenth. 10.10. 11.11. 12.12. 12.512.5 0=360=36 0=8.0=8.

Full solution

Q. y2\sqrt{y^{2}}zyzy\left\{\begin{array}{l}48=z(z+12)\48=z^{2}+62z\0=z^{2}+12z-408\0=3.2)(z-15.2)\$z=-3.2\quad z=15.2\end{array}\right. Find the diameter of o.O. A line that appears to be tangent is tangent. If your answer is not a whole number, round to the nearest tenth. 10.10. 11.11. 12.12. 12.512.5 0=360=36 0=8.0=8.
  1. Calculate rolls needed: Calculate the number of rolls needed by dividing the total amount of tape needed by the amount of tape on each roll. \newline8,000cm÷2,000cm/roll=4rolls8,000\,\text{cm} \div 2,000\,\text{cm}/\text{roll} = 4\,\text{rolls}
  2. Simplify absolute value: Simplify the equation by recognizing that y2\sqrt{y^{2}} is the absolute value of yy.y=zy|y| = zy
  3. Consider positive and negative cases: Since yy could be positive or negative, we consider both cases.\newlineCase 11: y=zyy = zy (if yy is positive)\newlineCase 22: y=zy-y = zy (if yy is negative)
  4. Case 11: y=zyy = zy: For Case 11, if y=zyy = zy, then y(1z)=0y(1 - z) = 0. This implies either y=0y = 0 or z=1z = 1.
  5. Case 22: y=zy-y = zy: For Case 22, if y=zy-y = zy, then y(1z)=0y(-1 - z) = 0. This implies either y=0y = 0 or z=1z = -1.
  6. Correct system of equations: The system of equations is incorrect. It should be:\newline48=z(z+12)48 = z(z + 12)\newline48=z2+12z48 = z^2 + 12z\newline0=z2+12z480 = z^2 + 12z - 48

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