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souve becow: 1
In 
Delta rem, 
m < k=(5x-2)^(@) 
m/_L=(4x-3)^(0), and 
m/_M=(x-10)^(@). find 
m/_L.

souve becow: 11\newlineIn Δ \Delta rem, m<k=(5x2) m<k=(5 x-2)^{\circ} mL=(4x3)0 m \angle L=(4 x-3)^{0} , and mM=(x10) m \angle M=(x-10)^{\circ} . find mL m \angle L .

Full solution

Q. souve becow: 11\newlineIn Δ \Delta rem, m<k=(5x2) m<k=(5 x-2)^{\circ} mL=(4x3)0 m \angle L=(4 x-3)^{0} , and mM=(x10) m \angle M=(x-10)^{\circ} . find mL m \angle L .
  1. Substitute Expressions: Step Title: Substitute the Given Expressions\newlineCalculation: Substitute m<km < k, m/Lm/_{L}, and m/Mm/_{M} with their respective expressions: (5x2)@+(4x3)0+(x10)@=180(5x-2)^{@} + (4x-3)^{0} + (x-10)^{@} = 180.
  2. Simplify Equation: Step Title: Simplify the Equation\newlineCalculation: Simplify the exponents and solve for xx: (5x2)2+(4x3)0+(x10)2=180(5x-2)^2 + (4x-3)^0 + (x-10)^2 = 180.