Solving Systems by Substitution Solve the system using substitution. {:[2x+2y=30],[y=4x],[(3","[?])]:}

Substitute y with 4x: First, let's substitute y with 4x in the first equation. 2x + 2(4x) = 30Simplify and solve for x: Now, simplify and solve for x. 2x + 8x = 30 10x = 30 x = 30 / 10 x = 3Substitute x back: Next, substitute x back into y = 4x to find y. y = 4(3) y = 12Check solutions: Finally, we check our solutions in the original equations. 2(3) + 2(12) = 30 6 + 24 = 30 30 = 30, which is true. And for the second equation, y = 4x 12 = 4(3) 12 = 12, which is also true.

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Solving Systems by Substitution
Solve the system using substitution.

{:[2x+2y=30],[y=4x],[(3","[?])]:}

Solve the system using substitution. $\newline$ $\begin{array}{l} 2 x+2 y=30 \\ y=4 x \\ (3,[?]) \end{array}$

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Grade 8

Solve a system of equations using substitution

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Q. Solve the system using substitution.

\newline

\begin{array}{l} 2 x+2 y=30 \\ y=4 x \\ (3,[?]) \end{array}

Substitute $y$ with $4x$ : First, let's substitute $y$ with $4x$ in the first equation. $2x + 2(4x) = 30$
Simplify and solve for x: Now, simplify and solve for x. $\newline$ $2x + 8x = 30$ $\newline$ $10x = 30$ $\newline$ $x = \frac{30}{10}$ $\newline$ $x = 3$
Substitute $x$ back: Next, substitute $x$ back into $y = 4x$ to find $y$ . $\newline$ $y = 4(3)$ $\newline$ $y = 12$
Check solutions: Finally, we check our solutions in the original equations. $\newline$ $2(3) + 2(12) = 30$ $\newline$ $6 + 24 = 30$ $\newline$ $30 = 30$ , which is true. $\newline$ And for the second equation, $\newline$ $y = 4x$ $\newline$ $12 = 4(3)$ $\newline$ $12 = 12$ , which is also true.