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SOLVING QUADRATIE
\newline
C. Determine the solutions of each quadratic equation using the factoring method.
\newline
x
2
+
5
x
+
6
=
0
x^{2}+5x+6=0
x
2
+
5
x
+
6
=
0
\newline
x
2
−
3
x
−
4
=
0
x^{2}-3x-4=0
x
2
−
3
x
−
4
=
0
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Math Problems
Precalculus
Factor sums and differences of cubes
Full solution
Q.
SOLVING QUADRATIE
\newline
C. Determine the solutions of each quadratic equation using the factoring method.
\newline
x
2
+
5
x
+
6
=
0
x^{2}+5x+6=0
x
2
+
5
x
+
6
=
0
\newline
x
2
−
3
x
−
4
=
0
x^{2}-3x-4=0
x
2
−
3
x
−
4
=
0
Factorize Quadratic Equation:
Factorize the first quadratic equation
x
2
+
5
x
+
6
=
0
x^2 + 5x + 6 = 0
x
2
+
5
x
+
6
=
0
.
\newline
(
x
+
3
)
(
x
+
2
)
=
0
(x + 3)(x + 2) = 0
(
x
+
3
)
(
x
+
2
)
=
0
, because
3
×
2
=
6
3 \times 2 = 6
3
×
2
=
6
and
3
+
2
=
5
3 + 2 = 5
3
+
2
=
5
.
Solve for x:
Solve for x from the factors of the first equation.
\newline
x
+
3
=
0
→
x
=
−
3
x + 3 = 0 \rightarrow x = -3
x
+
3
=
0
→
x
=
−
3
\newline
x
+
2
=
0
→
x
=
−
2
x + 2 = 0 \rightarrow x = -2
x
+
2
=
0
→
x
=
−
2
Factorize Second Equation:
Factorize the second quadratic equation
x
2
−
3
x
−
4
=
0
x^2 - 3x - 4 = 0
x
2
−
3
x
−
4
=
0
.
\newline
(
x
−
4
)
(
x
+
1
)
=
0
(x - 4)(x + 1) = 0
(
x
−
4
)
(
x
+
1
)
=
0
, because
−
4
×
1
=
−
4
-4 \times 1 = -4
−
4
×
1
=
−
4
and
−
4
+
1
=
−
3
-4 + 1 = -3
−
4
+
1
=
−
3
.
Solve for x:
Solve for x from the factors of the second equation.
\newline
x
−
4
=
0
→
x
=
4
x - 4 = 0 \rightarrow x = 4
x
−
4
=
0
→
x
=
4
\newline
x
+
1
=
0
→
x
=
−
1
x + 1 = 0 \rightarrow x = -1
x
+
1
=
0
→
x
=
−
1
More problems from Factor sums and differences of cubes
Question
Find the solutions of the quadratic equation
2
x
2
−
8
x
−
9
=
0
2 x^{2}-8 x-9=0
2
x
2
−
8
x
−
9
=
0
.
\newline
Choose
1
1
1
answer:
\newline
(A)
2
±
34
2
i
2 \pm \frac{\sqrt{34}}{2} i
2
±
2
34
i
\newline
(B)
−
2
±
34
2
i
-2 \pm \frac{\sqrt{34}}{2} i
−
2
±
2
34
i
\newline
(C)
2
±
34
2
2 \pm \frac{\sqrt{34}}{2}
2
±
2
34
\newline
(D)
1
±
34
4
1 \pm \frac{\sqrt{34}}{4}
1
±
4
34
Get tutor help
Posted 3 months ago
Question
x
3
+
7
x
2
−
36
x^{3}+7 x^{2}-36
x
3
+
7
x
2
−
36
\newline
The polynomial has zeros at
−
6
-6
−
6
and
2
2
2
. If the remaining zero is
z
z
z
, then what is the value of
−
z
-z
−
z
?
Get tutor help
Posted 3 months ago
Question
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
(
−
5
x
+
4
)
(
x
−
3
)
=
0
lesser
x
=
□
greater
x
=
□
\begin{array}{l} (-5 x+4)(x-3)=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}
(
−
5
x
+
4
)
(
x
−
3
)
=
0
lesser
x
=
□
greater
x
=
□
Get tutor help
Posted 3 months ago
Question
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
(
2
x
+
4
)
(
3
x
−
2
)
=
0
(2 x+4)(3 x-2)=0
(
2
x
+
4
)
(
3
x
−
2
)
=
0
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Posted 3 months ago
Question
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
(
3
x
−
6
)
(
−
x
+
3
)
=
0
lesser
x
=
□
greater
x
=
□
\begin{array}{l} (3 x-6)(-x+3)=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}
(
3
x
−
6
)
(
−
x
+
3
)
=
0
lesser
x
=
□
greater
x
=
□
Get tutor help
Posted 3 months ago
Question
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
(
x
+
6
)
(
−
x
+
1
)
=
0
(x+6)(-x+1)=0
(
x
+
6
)
(
−
x
+
1
)
=
0
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Posted 3 months ago
Question
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
3
x
2
+
2
f(x)=\frac{3}{x^{2}+2}
f
(
x
)
=
x
2
+
2
3
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Posted 3 months ago
Question
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
1
4
−
x
2
f(x)=\frac{1}{4-x^{2}}
f
(
x
)
=
4
−
x
2
1
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Posted 3 months ago
Question
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
2
∣
x
∣
−
5
f(x)=2|x|-5
f
(
x
)
=
2∣
x
∣
−
5
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Posted 3 months ago
Question
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
x
x
2
+
1
f(x)=\frac{x}{x^{2}+1}
f
(
x
)
=
x
2
+
1
x
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Posted 3 months ago