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Solve.\newliney=4y = 4\newline–8x+7y=–12–8x + 7y = –12\newline(_____, _____)

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Q. Solve.\newliney=4y = 4\newline–8x+7y=–12–8x + 7y = –12\newline(_____, _____)
  1. Substitute y=4y = 4: First, we substitute y=4y = 4 into the equation −8x+7y=−12-8x + 7y = -12. This gives us −8x+7(4)=−12-8x + 7(4) = -12. After simplifying, we get −8x+28=−12-8x + 28 = -12.
  2. Isolate −8x-8x: Next, we subtract 2828 from both sides of the equation to isolate −8x-8x. This gives us −8x=−12−28-8x = -12 - 28. After simplifying, we get −8x=−40-8x = -40.
  3. Solve for x: Finally, we divide both sides of the equation by −8-8 to solve for xx. This gives us x=−40/−8x = -40 / -8. After simplifying, we get x=5x = 5.
  4. Find coordinate point: We found y=4y = 4 and x=5x = 5. Substitute these values in (x,y)(x, y) to get the coordinate point.\newlineThis gives us the coordinate point (5,4)(5, 4).

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